x^2+5=(2x+1)(x-1)

Solution for x^2+5=(2x+1)(x-1) equation:

Simplifying
x2 + 5 = (2x + 1)(x + -1)

Reorder the terms:
5 + x2 = (2x + 1)(x + -1)

Reorder the terms:
5 + x2 = (1 + 2x)(x + -1)

Reorder the terms:
5 + x2 = (1 + 2x)(-1 + x)

Multiply (1 + 2x) * (-1 + x)
5 + x2 = (1(-1 + x) + 2x * (-1 + x))
5 + x2 = ((-1 * 1 + x * 1) + 2x * (-1 + x))
5 + x2 = ((-1 + 1x) + 2x * (-1 + x))
5 + x2 = (-1 + 1x + (-1 * 2x + x * 2x))
5 + x2 = (-1 + 1x + (-2x + 2x2))

Combine like terms: 1x + -2x = -1x
5 + x2 = (-1 + -1x + 2x2)

Solving
5 + x2 = -1 + -1x + 2x2

Solving for variable 'x'.

Reorder the terms:
5 + 1 + x + x2 + -2x2 = -1 + -1x + 2x2 + 1 + x + -2x2

Combine like terms: 5 + 1 = 6
6 + x + x2 + -2x2 = -1 + -1x + 2x2 + 1 + x + -2x2

Combine like terms: x2 + -2x2 = -1x2
6 + x + -1x2 = -1 + -1x + 2x2 + 1 + x + -2x2

Reorder the terms:
6 + x + -1x2 = -1 + 1 + -1x + x + 2x2 + -2x2

Combine like terms: -1 + 1 = 0
6 + x + -1x2 = 0 + -1x + x + 2x2 + -2x2
6 + x + -1x2 = -1x + x + 2x2 + -2x2

Combine like terms: -1x + x = 0
6 + x + -1x2 = 0 + 2x2 + -2x2
6 + x + -1x2 = 2x2 + -2x2

Combine like terms: 2x2 + -2x2 = 0
6 + x + -1x2 = 0

Factor a trinomial.
(3 + -1x)(2 + x) = 0

Subproblem 1
Set the factor '(3 + -1x)' equal to zero and attempt to solve:

Simplifying
3 + -1x = 0

Solving
3 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -1x = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -1x = 0 + -3
-1x = 0 + -3

Combine like terms: 0 + -3 = -3
-1x = -3

Divide each side by '-1'.
x = 3

Simplifying
x = 3
Subproblem 2
Set the factor '(2 + x)' equal to zero and attempt to solve:

Simplifying
2 + x = 0

Solving
2 + x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + x = 0 + -2

Combine like terms: 2 + -2 = 0
0 + x = 0 + -2
x = 0 + -2

Combine like terms: 0 + -2 = -2
x = -2

Simplifying
x = -2
Solution
x = {3, -2}